c# - How do I get the first element from an IEnumerable<T> in .net? -


I often refer to IEnumerable & lt; T & gt; I want to get the first element of .net in , and I have not found a good way to do this. I have come up with the best: 

  foreach (Elm e eMermerelabel) {// E do something with brake; }

Yuk! So, what is a good way to do this?

If you can use LINQ you can use: 

 < Code> var e = enumerable.First ();

This will throw an exception, though the calculable is empty: in which case you can use: 

  var e = enumerable.FirstOrDefault ();

First and default () will return default (t) if the calculable is empty, which will be null < Default 'zero-value' for / code> for reference types or for price types.

If you can not use LINQ, then your approach is technically correct and is not different from making a calculator using GetEnumerator to get the first result And moveNext methods (this example assumes that there is a IEnumerable & lt; Elem & gt; ): 

  Elem E = myDefault; (If (enumer.MoveNext ()) e = enumer.Current;}

using IEnumerator (EElformer & lt; Elem & gt; enumer = enumerable.GetEnumerator ()) . Single () in the comments; It will also work, if you are expecting to keep an element in your calculation - though it will throw an exception if it is either empty or from an element Large is a compatible single default () method that covers this scenario equally as first and default () . It is possible that single default () can also throw an exception in the case where there are more than one item in the number.

EDIT: Thank you for telling me that After using my IEnumerator object - I have edited the non-LINQ example to display this keyword using to apply the keyword.


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